4. 已知幂函数f(x)=(m2−2m−2)xmf(x)=(m^{2}-2m-2)x^{m}f(x)=(m2−2m−2)xm在(0,+∞)(0,+\infty )(0,+∞)上单调递减，则g(x)=loga(x+m)+2(a>0)g(x)=\log _{a}(x+m)+2(a>0)g(x)=loga(x+m)+2(a>0)的图象过定点((( )))