18.如图,矩形ABCDABCDABCD中,AD=2AB=102AD=\sqrt{2}AB=10\sqrt{2}AD=2AB=102,边ADADAD,BCBCBC的中点分别为EEE,FFF,直线BEBEBE交ACACAC于点GGG,直线DFDFDF交ACACAC于点HHH.现分别将ΔABE\Delta ABEΔABE,ΔCDF\Delta CDFΔCDF沿BEBEBE,DFDFDF折起,点AAA,CCC在平面BFDEBFDEBFDE同侧,则((( )))