9.如图,正方体ABCD−A1B1C1D1ABCD-A_{1}B_{1}C_{1}D_{1}ABCD−A1B1C1D1的棱长为2.(1)用空间向量方法证明:A1C1//A_{1}C_{1}//A1C1//平面ACD1ACD_{1}ACD1;(2)求直线BDBDBD与平面ACD1ACD_{1}ACD1所成角的正弦值.