18. 如图,四棱柱ABCD−A1B1C1D1ABCD-A_{1}B_{1}C_{1}D_{1}ABCD−A1B1C1D1中,底面ABCDABCDABCD为正方形,ACACAC与BDBDBD交于点OOO,平面A1C1CA⊥A_{1}C_{1}CA\botA1C1CA⊥平面ABCDABCDABCD,AB=2,AA1=2,CC1AB=\sqrt{2},A{A_1}=2,C{C_1}AB=2,AA1=2,CC1与底面ABCDABCDABCD所成的角为60∘60\circ60∘.(1)求证:C1O⊥C_{1}O\botC1O⊥平面ABCDABCDABCD;(2)求平面ACB1ACB_{1}ACB1与平面CDD1C1CDD_{1}C_{1}CDD1C1的夹角的余弦值.