3.已知正方体ABCD−A1B1C1D1ABCD-A_{1}B_{1}C_{1}D_{1}ABCD−A1B1C1D1中,AB=23AB=2\sqrt{3}AB=23,点EEE为平面A1BDA_{1}BDA1BD内的动点,设直线AEAEAE与平面A1BDA_{1}BDA1BD所成的角为α\alphaα,若sinα=255\sin \alpha =\frac{2\sqrt{5}}{5}sinα=525,则点EEE的轨迹所围成的面积为((( )))