1中等解答题14.(2023春•仁寿县校级期中)已知函数f(x)=lnx+ax2+(2a+1)xf(x)=lnx+ax^{2}+(2a+1)xf(x)=lnx+ax2+(2a+1)x. (1)当a=1a=1a=1时,求y=f(x)y=f(x)y=f(x)曲线在x=1x=1x=1处的切详情思路练习详情思路练习
2中等解答题18.(2023•德州三模)已知函数f(x)=lnx+12(a−x)2f(x)=lnx+\frac{1}{2}(a-x)^{2}f(x)=lnx+21(a−x)2,其中a∈Ra\in Ra∈R. (1)当a=1a=1a=1时,求函数f(x)f(x)f(x)在(1(1(1,fff(1))))处的切线方程; (2)讨论函数f(x)f(x)f(x)的单调性;详情思路练习详情思路练习
3中等解答题10.(2023春•唐山期末)已知函数f(x)=ex−ax−1f(x)=e^{x}-ax-1f(x)=ex−ax−1. (1)讨论函数f(x)f(x)f(x)的单调性; (2)若f(x)f(x)f(x)有且仅有2个零点,求实数aaa的取值范围.详情思路练习详情思路练习
4中等解答题9.(2023春•芗城区校级月考)已知函数f(x)=ex−2ax(a∈R)f(x)=e^{x}-2ax(a\in R)f(x)=ex−2ax(a∈R). (1)讨论函数f(x)f(x)f(x)的单调区间;详情思路练习详情思路练习
5中等解答题11.(2023春•锦州期末)已知函数f(x)=13x3−12ax2f(x)=\frac{1}{3}{x}^{3}-\frac{1}{2}a{x}^{2}f(x)=31x3−21ax2. (1)若x=1x=1x=1是函数f(x)f(x)f(x)的极小值点,求aaa的值; (2)讨论f(x)f(x)f(x)的单调性.详情思路练习详情思路练习
6中等解答题4.(2023春•铁西区校级期中)已知函数f(x)=13x3+ax2−3a2x+1(a∈R)f(x)=\frac{1}{3}{x}^{3}+a{x}^{2}-3{a}^{2}x+1(a\in R)f(x)=31x3+ax2−3a2x+1(a∈R). (1)详情思路练习详情思路练习
7中等解答题8.(2023春•怀仁市期末)已知函数f(x)=(x−2)ex−a2x2+axf(x)=({x-2}){e^x}-\frac{a}{2}{x^2}+axf(x)=(x−2)ex−2ax2+ax,a∈Ra\in Ra∈R. (1)若a=0a=0a=0时,详情思路练习详情思路练习