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#16cacff2-033b-4dfa-8234-ee2cfcd86b90中等解答题空间中的角度立体几何

4.如图,在四棱柱ABCDA1B1C1D1ABCD-A_{1}B_{1}C_{1}D_{1}中,侧棱A1AA_{1}A\bot平面ABCDABCDAB//DCAB//DCABADAB\bot ADAD=CD=2AD=CD=2AA1=AB=4AA_{1}=AB=4EE为棱AA1AA_{1}的中点.
(1)证明:BCC1EBC\bot C_{1}E
(2)设CM=λCE(0<λ<1)\overrightarrow{CM}=\lambda \overrightarrow{CE}(0<\lambda <1),若C1C_{1}到平面BB1MBB_{1}M的距离为255\frac{2\sqrt{5}}{5},求λ\lambda