8.已知椭圆C:x2a2+y2b2=1(a>b>0)C:\frac{x^2}{a^2}+\frac{y^2}{b^2}=1(a>b>0)C:a2x2+b2y2=1(a>b>0)的离心率e=22e=\frac{\sqrt{2}}{2}e=22,且椭圆CCC经过点(1,22)(1,\frac{\sqrt{2}}{2})(1,22).(1)求椭圆CCC的标准方程;(2)过点P(2,0)P(2,0)P(2,0)且斜率不为零的直线与椭圆CCC交于BBB,DDD两点,BBB关于xxx轴的对称点为AAA,求证:直线ADADAD与xxx轴交于定点QQQ.