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#f8d0838c-7f90-448d-a225-88a160c5050d中等解答题定点定值问题直线与圆+圆锥曲线

6.已知两定点A(3,0)A(-3,0)B(3,0)B(3,0),过动点PP的两直线PAPAPBPB的斜率之积为89-\frac{8}{9}.设动点PP的轨迹为CC
(1)求曲线CC的方程;
(2)设F1(1,0)F_{1}(-1,0),过F1F_{1}的直线ll交曲线CCMMNN两点(不与AABB重合).设直线AMAMBNBN的斜率分别为k1k_{1}k2k_{2},证明k1k2\frac{k_1}{k_2}为定值.