25.在长方体ABCD−A1B1C1D1ABCD-A_{1}B_{1}C_{1}D_{1}ABCD−A1B1C1D1中,AA1=1AA_{1}=1AA1=1,A1D1=1A_{1}D_{1}=1A1D1=1,AB=2AB=\sqrt{2}AB=2,MMM为D1BD_{1}BD1B上一动点,NNN为ABABAB上一动点,则2A1M+2MN2{A}_{1}M+\sqrt{2}MN2A1M+2MN的最小值为 [ 3 ]{.underline}.